更新时间:2020-08-13 16:35:51 来源:极悦 浏览2189次
问题描述
启动3个线程打印递增的数字,线程1先打印1,2,3,4,5,然后是线程2打印6,7,8,9,10,然后是线程3打印11,12,13,14,15.接着再由线程1打印16,17,18,19,20….以此类推,直到打印到75.程序的输出结果应该为:
线程1:1
线程1:2
线程1:3
线程1:4
线程1:5
线程2:6
线程2:7
线程2:8
线程2:9
线程2:10
…
线程3:71
线程3:72
线程3:73
线程3:74
线程3:75
解法一:
class PrintRunnable implements Runnable {
private static volatile int printNum = 0;
private int threadId;
private Object o;
public PrintRunnable(int threadId,Object o){
this.threadId = threadId;
this.o=o;
}
@Override
public void run() {
while(printNum < 75){
synchronized (o){
if (printNum/5%3 + 1 == threadId){
//该判断确保对应线程输出
for (int i = 0; i <5; i++) {
System.out.println("线程"+threadId+":"+(++printNum));
}
o.notifyAll();
}else {
try {
o.wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}
}
}
public class Main {
public static void main(String[] args) throws InterruptedException {
Object o = new Object();
new Thread(new PrintRunnable(1,o)).start();
new Thread(new PrintRunnable(2,o)).start();
new Thread(new PrintRunnable(3,o)).start();
}
}
解法二:
public class Print123456 implements Runnable{
private String name;
private Object prev;
private Object self;
private int count;
public Print123456(String name,Object prev,Object self,int count){
this.name=name;
this.prev=prev;
this.self=self;
this.count=count;
}
@Override
public void run() {
while(count<=75){
synchronized (prev){
synchronized (self){
for (int i=0;i<5;i++){
count=count+1;
if(count>75)break;
System.out.println(name+": "+count);
}
count=count+10;
//System.out.println("释放自身锁,并唤醒在等待该锁的线程");
self.notify();//释放自身锁,并唤醒在等待该锁的线程
}
//System.out.println("释放自身锁成功");
try {
//System.out.println("等待前一个锁");
prev.wait();//等待前一个锁
} catch (InterruptedException e) {
e.printStackTrace();
}
}
//System.out.println("两个锁全部释放,重新进入新的循环,但是由于有prev.wait()所以该线程等待获取prev的锁");
}
}
}
public class Main {
public static void main(String[] args) throws InterruptedException {
Object a=new Object();
Object b=new Object();
Object c=new Object();
Print123456 A=new Print123456("线程1",c,a,0);
Print123456 B=new Print123456("线程2",a,b,5);
Print123456 C=new Print123456("线程3",b,c,10);
new Thread(A).start();
Thread.sleep(100);
new Thread(B).start();
Thread.sleep(100);
new Thread(C).start();
Thread.sleep(100);
}
}
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